How can 2 inch gap be a substitute for thickness?.. = 12inches seems a tall claim.. Probably 8 (or) 9 inch inch at best..
Am trying to interpret the absorption co-efficient from the table that was shared earlier..
From the the above table, as the thickness increases for the same density, absorption at low freq (below 250) seems higher..
On wall for same density (48 Kg/m3) - 3 inch panel has 0.53 for 125 Hz and 1.19 for 250Hz, but at 6 inches it is 1.19 for 125Hz and 1.21 for 250Hz..
If a 6inch panel can absorb more lows, then why use airgap for 3 (or) 4 inch panel?.. Drawing inferences from the table, an 8 inch panel on wall with same density would absorb even more lows, negating the airgap required..
Hmm.. I think it would be impractical to have it 16 inches away from wall..
Just for calculation & reasoning :
2 inch panel onwall (48kg/m3)+ 16 inch airgap makes 0.40 at 125Hz.. But, 3 inch thickness onwall of (48kg/m3) does 0.53 at 125Hz.. I think you would save 15inch of space..